Reliable Oracle 1z0-071 Study Notes | Latest 1z0-071 Exam Topics

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Oracle Database SQL Sample Questions (Q76-Q81):

NEW QUESTION # 76
Evaluate the following query

What is the correct output of the above query?

A. +00-300, +54-02, +00 11:12:10.123457
B. +25-00, +00-650, +00 11:12:10.123457
C. +00-300, +00-650, +00 11:12:10.123457
D. +25-00, +54-02, +00 11:12:10.123457

Answer: D

NEW QUESTION # 77
Which two statements are true about the results of using the INTERSECT operator in compound queries?

A. Reversing the order of the intersected tables can sometimes affect the output.
B. Column names in each SELECT in the compound query can be different.
C. The number of columns in each SELECT in the compound query can be different.
D. INTERSECT returns rows common to both sides of the compound query.
E. INTERSECT ignores NULLs

Answer: B,D

Explanation:
In Oracle Database 12c, the INTERSECT operator is used in compound queries to return only the rows that are common to both SELECT statements involved in the query. Here's a breakdown of why the correct answer is C:
* A: Incorrect. The order of the tables in an INTERSECT operation does not affect the output because INTERSECT returns only the common elements between the two queries. The operation is symmetric.
* B: Incorrect. While the column names themselves can differ between the two SELECT statements, the data types and the number of columns must match for INTERSECT to function correctly.
* C: Correct. INTERSECT returns the intersection of the results of the two queries, which includes only rows that are found in both result sets.
* D: Incorrect. The number of columns and their data types in each SELECT statement of the INTERSECT must be the same to avoid errors and to correctly perform the comparison.
* E: Incorrect. INTERSECT does not ignore NULLs; rows with NULL values in corresponding columns must exactly match (both sides having NULLs in the same column) to be included in the output.

NEW QUESTION # 78
Examine the structure of the MEMBERS table: (Choose the best answer.)
Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC; What would be the result execution?

A. It displays all cities in ascending order, within which the last names are further sorted in descending order.
B. It displays all cities in descending order, within which the last names are further sorted in descending order.
C. It fails because a column alias cannot be used in the ORDER BY clause.
D. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.

Answer: A

NEW QUESTION # 79
View the Exhibit and examine the structure of the PORDUCT_INFORMATION table. (Choose the best answer.)

PRODUCT_ID column is the primary key.
You create an index using this command:
SQL > CREATE INDEX upper_name_idx
ON product_information(UPPER(product_name));
No other indexes exist on the PRODUCT_INFORMATION table.
Which query would use the UPPER_NAME_IDX index?

A. SELECT UPPER(product_name)
FROM product_information;
B. SELECT UPPER(product_name)
FROM product_information
WHERE product_id = 2254;
C. SELECT product_id, UPPER(product_name)
FROM product_information
WHERE UPPER(product_name) = 'LASERPRO' OR list_price > 1000;
D. SELECT product_id
FROM product_information
WHERE UPPER(product_name) IN ('LASERPRO', 'CABLE');

Answer: D

NEW QUESTION # 80
Examine the description products table:

Examine the description of the new_projects table;

Which two queries execute successfully?

Answer: C,E

Explanation:
To determine which queries will execute successfully, we need to consider the compatibility of the column definitions and the structure of the SELECT statements:
* Option A uses the MINUS set operator, which subtracts rows returned by the second SELECT statement from the rows returned by the first. For MINUS to work, the number and the order of columns and their data types must be the same in both queries. This query will not execute successfully because the second SELECT statement does not include all columns from the first SELECT statement, and the data types and sizes of PROD_ID do not match (CHAR(2) vs CHAR(4)).
* Option B uses the UNION ALL set operator, which appends the results of the second SELECT statement to the results of the first. Unlike UNION, UNION ALL does not eliminate duplicate rows.
This query will execute successfully because UNION ALL does not require the same data types or sizes, and the result will contain all columns from the first SELECT statement filled with NULL for non-matching columns from the second SELECT statement.
* Option C uses the UNION set operator, which requires the same number of columns and compatible data types. This query will not execute successfully because PROD_NAME has different data types (CHAR(4) vs VARCHAR2(10)), and the result of a UNION must have the same number of columns with compatible data types in the two SELECT statements.
* Option D uses the UNION set operator as well, but unlike Option C, it does not require a specific data type match because both SELECT statements include all columns and UNION is used (which will automatically handle type conversion where necessary). This query will execute successfully.
* Option E uses the INTERSECT set operator, which requires the same number and order of columns and their data types to be identical or compatible. This query will not execute successfully because the data types and sizes of PROD_ID do not match (CHAR(2) vs CHAR(4)).
References:
* Oracle Documentation on Set Operators: SQL Language Reference - Set Operators
* Oracle Documentation on Data Type Precedence: SQL Language Reference - Data Type Precedence In conclusion, only Option B and Option D will execute successfully because they adhere to the rules of the UNION ALL and UNION operators respectively, regarding column count and data type compatibility.

NEW QUESTION # 81
......

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RELIABLE ORACLE 1Z0-071 STUDY NOTES | LATEST 1Z0-071 EXAM TOPICS

Reliable Oracle 1z0-071 Study Notes | Latest 1z0-071 Exam Topics